x^2+x=3.3

Solution for x^2+x=3.3 equation:

x^2+x=3.3

We move all terms to the left:

x^2+x-(3.3)=0

We add all the numbers together, and all the variables

x^2+x-3.3=0

a = 1; b = 1; c = -3.3;
Δ = b2-4ac
Δ = 12-4·1·(-3.3)
Δ = 14.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{14.2}}{2*1}=\frac{-1-\sqrt{14.2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{14.2}}{2*1}=\frac{-1+\sqrt{14.2}}{2}
$